CCNA NAT SIM Question 2

I was trying to clarify something.

Why do we need to use the OVERLOAD statement making it a Pat? I understand its for simultaneous connections.

Would any of addresses in the pool get used aside from the first one if Pat is being used?

The company has 62 hosts that need to access the internet simultaneously but we just have 6 public IP addresses from 198.18.32.65 to 198.18.32.70/29, so we have to use PAT.

When using the OVERLOAD statement, you will only use the first ip address. It is a bit weird, but it satisfies all the requirements and it is the only way we can do.

I didn’t understand in this statement ( access-list 1 permit 192.168.6.64 0.0.0.63) where 63 comes from, why we write 63 ?

This is a /26 network. There network address is 192.168.6.64.0. Its mask will be 255-(128+64) which is 63. Remember we borrowed 2 bits.

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@Anonymous: 63 is wildcard mask of this ip.
here see
access-list 1 permit 192.168.6.64 0.0.0.63
1 represents that it is standard access list permit is to give permisson to this ip address and after that IP address and wildcard mask is given of this ip
Remembe: Wildcard mask is reciprocal of subnet mask

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@ 9tut,

I think you’re just partly right. It will use only the first address of the pool for so long there are free ports left. Every connection (usually multiple and simultaneous on one host) will use a port of the global address.
As PAT will/can “only” 65536 ports minus the well-known ports at a certain point (with enough hosts on the inside having connections to the outside) it will run out for that one and first address.
I believe it will then use the next address (and the next if that one will run out and..etc.)

I also believe this will occur only in larger organizations.

Kind regards

@Anonymous:

I believe the wildcardmask is just the opposit of the subnet mask.
Then again, its mask will be 256-(128+64) which is 64.
You just need the count the 0.

A wildcard mask of 0.0.0.63 covers 64 adresses: 0, 1, 2, 3, 4, …, 62, 63, 64.

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How the ping will work ?
i think it will not work
because nat will assign PC2 IP in the range 198.18.32.65/29 -> 198.18.32.70/29 which is in different sub-net than router ISP (192.0.2.114/30).

so how the will ping work ?
can you pls. explain.

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Sorry i forget the default route on ISP S0/1
It should definitely work

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Does anyone have this in opacket tracer?

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Comment from 9tut in example NAT1 to know how the value 15 came
—————————————————————————————
You can quickly figure out what the wildcard is by reversing the bits from the subnet mask. In this case the subnet mask is /28, its last octet is 1111 0000 so we reverse it into 0000 1111 = 15

Doubt in NAT2 …??
———————–
How we got value 63 then? Subnet mask is /26, last octet is 1100 0000 so we reverse it into 0000 1100 which gives 12 ??

I know I am missing something? Can anyone explain plz!!

Thank you.

On this Q:CCNA NAT SIM Question 2(October,23rd/2010). on this line with this

Router1(config)#access-list 1 permit 192.168.6.64 0.0.0.63 so I’m not understand properly where comes the wildcard mask.
Plz any can explain to me.

to get the will card you that 192.168.6.24 with mask of 255.255.255.192. Just take 255.255.255.255 and subtract 255.255.255.192 which will give the wild card of 0.0.0.63

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Also in the access-list statement: access-list 1 permit 192.168.6.64 0.0.0.63, shouldn’t we av another statement: access-list 1 deny any after… Answer any1 ASAP

exam is exactly testinside 17.14
only ip changes……

Has any1 done the CCNA exam since yesterday… Please give latest updates… Which labs came on the exam… Thanks in advance

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@9tut.com
hi please let me know how this ping command works when we use private ip address in range from 192.168.6.65 – 126
and we ping the network 192.0.2.114

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thank y’all.

let me first say- i goofed. i didn’t go through the tutorial at the beginning of the test. on the second lab there were 5 questions. i answered the first question and hit “next”, instead hitting the box at the top of the screen “question 2″. i think i did get a pop-up that said are you sure you want to go to next question? but i mistakenly thought they meant next question in lab.

and when i saw what i had done i yelled out “F*UCk”!!!!! which really freaked out the other guy in the room. so i then said “sorry”.

i got an 809 and needed an 825. i feel like i would have passed if i had answered every other question in the lab. on the remaining questions after i goofed on the lab i was rattled and didn’t concentrate as well as i should have.

SO- go through the tutorial at the beginning of the test even though you don’t think you need to. and pay attention to how cisco wants you answer the questions. also, be advised there are many router commands you cannot use without proper syntax, (such as copy run start instead of copy running-config startup-config).

i finished the test with under 5 minutes left. so be careful of your time as well. there were 1 or 2 conceptual questions that i’ve never seen in any of my study materials too. cisco does state that some questions do not count for point and are simply there to see if they should be included in future tests. however, you still have to spend TIME on them. for me- the test felt very much like a race.

i know alot of people here passed and did a great job- congratulations to all of you. to all candidates that haven’t taken the test yet, PAY ATTENTION to how cisco wants you to answer the question. even though you know the answer if you make a mistake and click through you cannot go back.

I complained to the test center and they were kind enough to generate an incident report so maybe there’a a remoter chance i’ll get a voucher for next time. i’ll let you guys know if i do.

best to all of you,

C

Hi Friends
Has any1 done the CCNA exam since yesterday… Please give latest updates… Which labs came on the exam… Thanks in advance
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Wao,this site has been useful as i gives me an insight on what to expect as i am still a fresher in networking,thanks 9tut and keep it up.

good

hi 9 tut – i would like to ask on where did the address 192.168.6.64 0.0.0.63 came from ?

is it because of /26 ? = increment of 64

255.255.255. 128 64 / 32 16 8 4 2 1

.64 seems to be the network address – can anyone help me on this – thanks in advance

9Tut – got two questions here

1. on the nat sim 2 – what do we need to place on

ip nat pool public ip range ? or private ip range ?

both sims are using the direction of going out to the internet from the local host

please clarify

@drake: Yes /26 means “increment of 64″. And 192.168.6.64 is the network address as access list need a network address here + wildcard mask to specify a range of IP addresses.

We need to place public IP addresses in the ip nat pool

@ 9tut

what will happen if i didn’t write ” OVERLOAD ” in
Router1(config)#ip nat inside source list 1 pool mypool overload

i guess it will still valid ( Dynamic NAT )

plz help !!
thnx

Isn’t it better to use extended access list in this question.. bcoz the question states that we have to allow the hosts for internet access.. so the pinging should not work… plz reply….!!

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i am sitting for the exam on monday

everything appears OK but in the end, why is testing the connectivity performed to ISP?
I found enough pinging to 113, why 114?

wildcard bitmask

Calculating wildcard masks can be difficult, but you can do it
easily by subtracting the subnet mask from 255.255.255.255.
Example 1: assume you wanted to permit access to all users in
the 192.168.3.0 network.
–Because the subnet mask is 255.255.255.0, you could take the
255.255.255.255 and subtract from the subnet mask.
–The solution produces the wildcard mask 0.0.0.255.
Example 2: Now assume you wanted to permit network access
for the 14 users in the subnet 192.168.3.32 /28. The subnet mask
for the IP subnet is 255.255.255.240,
–take 255.255.255.255 and subtract the subnet mask
255.255.255.240
–The solution this time produces the wildcard mask 0.0.0.15.
Example 3: assume you wanted to match only networks
192.168.10.0 and 192.168.11.0.
–take 255.255.255.255 and subtract the subnet mask 255.255.254.0.
–The result is 0.0.1.255

wildcard mask 0.0.0.63
network :
These local hosts use private IP addresses in the 192.168.6.65 – 192.168.6.126/26 range.
/26 =255.255.255.192

255.255.255.255
-
255.255.255.192
= 0 . 0. 0. 63 wildcard mask

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Thanks in advance!

NAT?
PAT?
OVERLOADING?

Please write work of these

@Ice Man.. I get the wildcard now, but not sure why picked 192.168.6.64 instead of 192.168.6.65 in “access-list 1 permit 192.168.6.64 0.0.0.63″.

Network /26 255.255.255.128
64 address per Bloc
You have 62 for host
Cant use first address in rang is use for network address and last address use for network broadcast address

192.168.6.0 – 192.168.6.63 = 64 address
192.168.64 – 192.168.6.127 = 64 address
62 clients that needs to have simultaneous internet access. These local hosts use private IP addresses in the 192.168.6.65 – 192.168.6.126/26 range.
192.168.64 is the start of the address range
and you use 192.168.6.64 wildcard mask of this ip 0.0.0.63

Hope this is understandable I’m learning this myself now.

You have to count from start address 192.168.0 last address 192.168.6.63 = 64 address
192.168.0 = 1 address
192.168.0 – 192.168.6.63 = 63 address
1+63 = 64 address

You have to count from start address 192.168.64 last address 192.168.6.127 = 64 address
192.168.64 = 1 address
192.168.64 – 192.168.6.127 = 63 address
1+63 = 64 address

DaMan

today i have a test so guyz plz pray for me !!!

Shahid – How was the exam?

I still didn’t understand the usage of Overload Keyword

Hello please can someone send me the packet tracer sim for this particular question, have exam on 17th of march. Thanks for helping me out email== markdganish@yahoo.com

Does anyone have the Packet Tracer sims for this example along with the VTP, ACL 2 and EIGRP (AS) examples that are on this site? If so please email them to me at nbackus08@gmail.com

Much obliged,
Nate

access-list 1 permit 192.168.6.64 0.0.0.63

why not

access-list 1 permit 192.168.6.65 0.0.0.63 ?

thanks

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“192.168.0″ Sorry I forgot 6
You have to count from start address 192.168.6.0 last address 192.168.6.63 = 64 address
192.168.6.0 = 1 address
192.168.6.0 – 192.168.6.63 = 63 address
1+63 = 64 address

You have to count from start address 192.168.64 last address 192.168.6.127 = 64 address
192.168.6.64 = 1 address
192.168.6.64 – 192.168.6.127 = 63 address

Network /26 255.255.255.128
64 address per Bloc
You have 62 for host
Cant use first address in rang is use for network address and last address use for network broadcast address

192.168.6.0 – 192.168.6.63 = 64 address
192.168.64 – 192.168.6.127 = 64 address
62 clients that needs to have simultaneous internet access. These local hosts use private IP addresses in the 192.168.6.65 – 192.168.6.126/26 range.
192.168.64 is the start of the address range
and you use 192.168.6.64 wildcard mask of this ip 0.0.0.63

Hope this is understandable I’m learning this myself now.

1+63 = 64 address

wildcard bitmask

Calculating wildcard masks can be difficult, but you can do it
easily by subtracting the subnet mask from 255.255.255.255.
Example 1: assume you wanted to permit access to all users in
the 192.168.3.0 network.
–Because the subnet mask is 255.255.255.0, you could take the
255.255.255.255 and subtract from the subnet mask.
–The solution produces the wildcard mask 0.0.0.255.
Example 2: Now assume you wanted to permit network access
for the 14 users in the subnet 192.168.3.32 /28. The subnet mask
for the IP subnet is 255.255.255.240,
–take 255.255.255.255 and subtract the subnet mask
255.255.255.240
–The solution this time produces the wildcard mask 0.0.0.15.
Example 3: assume you wanted to match only networks
192.168.10.0 and 192.168.11.0.
–take 255.255.255.255 and subtract the subnet mask 255.255.254.0.
–The result is 0.0.1.255

wildcard mask 0.0.0.63
network :
These local hosts use private IP addresses in the 192.168.6.65 – 192.168.6.126/26 range.
/26 =255.255.255.192

255.255.255.255
-
255.255.255.192
= 0 . 0. 0. 63 wildcard mask

SIMPLE EXPLANATION WOULD BE……………

HOST IP’S RANGE = 192.168.6.65 – 192.168.6.126 (THESE ARE ADDRESSES THAT CAN BE ASSIGNED TO THE HOSTS)

NOTE: WE NEED TO PROVIDE THE N/W RANGE IN THE ACCESS-LIST ——-> SO THE N/W RANGE WOULD INCLUDE TWO MORE IP’S, WHICH ARE THE NETWORK ID(FIRST IP IN THE N/W IP RANGE) AND THE BROADCAST IP (LAST IP ADDRESS) ———-> SO THIS MEANS WE HAVE TO ADD THOSE SO WE CAN HAVE THE N/W RANGE ———> 192.168.16.64( .64 = N/W ID) – 192.168.16.127(.127=BROADCAST IP)

ALSO YOU CAN THINK OF THE /26 AND FIND THE INCRE., WHICH WOULD BE 64 ——> SO “/26″ NETWORKS HAVE THE NETWORK RANGES: XXXX.XXXX.XXXX.0 – XXXX.XXXX.XXXX.63
XXXX.XXXX.XXXX.64 – XXXX.XXXX.XXXX.127

hi guys,

why I could not ping any IP of my ip nat pool mypool 198.18.32.65 198.18.32.70 from router and any host ??

thx

Is there any change in dumps with in last 2 months….

hi all pls dump me z latest lab exam

Hi,

@9tut..
its saying in the question to click on the pc console to gain access to Router1.
My question is that will I get the access directly after clicking the PC or I need to telnet?
please help me ..

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I did the answer on a notepad without looking at the answer, but the only mistake I made was I used last IP 192.168.6.126 instead of 192.168.6.64 for the interface. I learnt to put 192.168.6.126 from CCNA NAT SIM Question 1

here was my answer

access-list 1 permit 192.168.6.126 0.0.0.63
ip nat pool NATPOOL 198.18.32.65 198.18.32.70 netmask 255.255.255.248
ip nat inside source list 1 pool NATPOOL overload

————————————————————————————————

access-list standard MYPOOL
permit 192.168.6.126 0.0.0.63

ip nat pool NATPOOL 198.18.32.65 198.18.32.70 netmask 255.255.255.248
ip nat inside source list MYPOOL pool NATPOOL overload

interface fastethernet 0/0: ip nat inside
interfasce serial 0/0: ip nat outside

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DId anybody take the CCNA exam recently? Did this sim came in the test?

Most people tell me they got 3 Sims and they where the ACL2, EIGRP and VTP one.

Can we use TAB button in the exam or what???

hey guys i know that i shouldnt be askin this but

i’m havin this error when i key in the subnet for my packet tracer question
router int fa0/0
ip add 192.168.6.64 255.255.255.192 cuz it’s /26 right?
but after i enter i’m havin Bad mask /26
why ?
is it cuz the subnet muz be 255.255.255.128? and why 128 instead of 192 for /26

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Litz,

your ip add is not valid. It’s a network id. /26 means the incremental value will be 64. so use 65 to 126.

hi Every body ,my Exam after 2 days ,i study well but am afraid too can any body send me the last dumps ,i will be thankfull
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Can someone kindly send me the latest dumps for CCNA 802 exam to cts1234586@hotmail.com
Many Thanks

I can’t access ISP’s Router…when I ping that Router than I get a message “Destination host unreachable” please help me in this regards while I do basic configuration on my both routers and allow NATing as mention in this SIM…So why I get an error of DESTINATION HOST UNREACHABLE….. I think connection between two Routers is not correct that’s y I got an error…

Please seniors help me….and also tell me where I am making a mistake in topology.

Regards
Zuhaib Siddiqui.

Hi,

About NAT Sim why we don’t have route or default route to destination, if the real world when we configure NAT we need to have default route. and if the Sim appear in exam can we configure default route or not?

Please help me about that point.

Thank you,

Dol Meun

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In real time why we are moving to NAT and tell me purpose

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Sorry i can’t mail everyone into individual
So i update in 9tut and Exam collection and it will use for all
Note:
Dont worry about commands you can use short commands in CLI (command line interface) as shown below:
1. Show mac address-table you can write in short show mac + tab it will appear full command (and please be noted don’t use show mac-address-table use only show mac address-table(don’t use ‘-‘ between mac and address, because the reason is, In new switches don’t use show mac-address-table it will commanded as show mac address-table keep it in mind this one(The command show mac address-table will display the forward/filter table, also called a CAM table on a switch))
2. Show running-config you can use as show run
3. Copy running-config startup-config you can use as copy run start
4. And more short command you can use CLI
5. In EIGRP don’t forget to add no-auto summary that to new added router because The network considered a discontiguous network because you have one classful address subnetted and separated by another classful address. Only RIPv2, OSPF, and EIGRP can work with discontiguous networks, but RIPv2 and EIGRP won’t work by default. You must use the no auto-summary command under the routing protocol configuration.
6. And don’t forget to ping to all routers when u doing lab in EIGRP and ACL don’t forget to ping and web browser to check okay
Please understand the concept and take exam when u read each question understand why this is the answer that one you know.
And Be carefull in Switching means you get one question which is root, designated by four switch mac address least mac-address will be the root bridge that port is connect to other switch. The root bridge receiving from other port that is root and second lower mac address is designated to other switch but not to root bridge.
Thank u 9tut and Exam collection
Any Regard Query or Question
Update comments in the 9tut or examcollection comments.

Hi Friends, I am taking the exam on the 19th of june can you pls send me the latest exam dump. I still feel so lost and I have almost gone through everything.

i want to take the ccna exam this month can any one give me the latest dumps i will b very thank ful thanks.
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Is anyone able to download this sim ?

Hi Nigel,

Link appears dead. Here is a link that includes a load of the sims from this site, maybe all. It has the nat sim in it. http://www.9tut.com/download/CCNA_DragDrop_EIGRP_RIP_NAT_and_implementation_LabsInPacketTracer.zip

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