Real CCNA 640-802 Questions and Answers

 
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CCNA Drag and Drop Questions 2

Here you will find answers to CCNA Drag and Drop Questions - Part 2

Question 1

The left describes OSI layers, while the right provides some terms. Drag the items on the right to the proper locations.

OSILayers.jpg

 

Answer:

Network Layer:

1) IP addresses
2) packets
3) routing

Transport Layer:

1) windowing
2) UDP
3) segments

Question 2

The above describes some categories, while the below provides their corresponding router output lines. Drag the above items to the proper locations.

Layer_Problems copy.jpg

 

Answer:

1) Port operational: Serial0/1 is up, line protocol is up
2) Layer 2 problem: Serial0/1 is up, line protocol is down
3) Layer 1 problem: Serial0/1 is down, line protocol is down
4) Port disabled: Serial0/1 is administrator down, line protocol is down

Explanation:

A simple way to find out which layer is having problem is to remember this rule: "the first statement is for Layer 1, the last statement is for Layer 2 and if Layer 1 is down then surely Layer 2 will be down too", so you have to check Layer 1 before checking Layer 2. For example, from the output "Serial0/1 is up, line protocol is down" we know that it is a layer 2 problem because the first statement (Serial0/1 is up) is good while the last statement (line protocol is down) is bad. For the statement "Serial0/1 is down, line protocol is down", both layers are down so the problem belongs to Layer 1.

There is only one special case with the statement ".... is administrator down, line protocol is down". In this case, we know that the port is currently disabled and shut down by the administrators.

Question 3

A user is unable to connect to the Internet. Based on the layered approach to troubleshooting and beginning with the lowest layer. Follow the guide and drag the contents to relevant modules.

Layered_Trobleshooting.jpg

 

Answer:

1) Verify Ethernet cable connection: Step 1
2) Verify NIC operation: Step 2
3) Verify IP configuration: Step 3
4) Verify URL: Step 4

Explanation:

The question asks us to "begin with the lowest layer" so we have to begin with Layer 1: verify physical connection; in this case an Ethernet cable connection. For your information, "verify Ethernet cable connection" means that we check if the type of connection (crossover, straight-through, rollover...) is correct, the RJ45 headers are plugged in, the signal on the cable is acceptable...

Next we "verify NIC operation". We do this by simply making a ping to the loopback interface 127.0.0.1. If it works then the NIC card (layer 1,2) and TCP/IP stack (layer 3) are working properly.

Verify IP configuration belongs to layer 3. For example, checking if the IP can be assignable for host, the PC's IP is in the same network with the gateway...

Verifying the URL by typing in your browser some popular websites like google.com, microsoft.com to assure that the far end server is not down (it sometimes make we think we can't access to the Internet). We are using a URL so this step belongs to layer 7 of the OSI model. 

Question 4

The left describes the types of cables, while the right describes the purposes of the cables. Drag the items on the left to the proper locations. (Not all items can be used).

TypesOfCables.jpg

 

Answer:

1) straight-through: switch access port to router
2) crossover: switch to switch
3) rollover: PC COM port to switch

Explanation:

To remember which type of cable you should use, follow these tips:

- To connect two serial interfaces of 2 routers we use serial cable
- To specify when we use crossover cable or straight-through cable, we should remember:
Group 1: Router, Host, Server
Group 2: Hub, Switch
One device in group 1 + One device in group 2: use straight-through cable
Two devices in the same group: use crossover cable

For example: we use straight-through cable to connect switch to router, switch to host, hub to host, hub to server... and we use crossover cable to connect switch to switch, switch to hub, router to router, host to host... )

Question 5

The left describes the types of switch ports, while the right describes the features. Drag the options on the right to the proper locations.

AccessPort_TrunkPort.jpg

 

Answer:

Access Port:

- Carries traffic for a single VLAN
- Uses a straight-through cable to connect a device
- Connects an end-user workstation to a switch

Trunk Port:

- Carries traffic for a multiple VLAN
- Uses 802.1q to identify traffic from different VLANs
- Facilitates interVLAN communications when connected to a Layer 3 device

Question 6

The above describes the Spanning-Tree Protocol port states, while the below describes their functions. Drag the above items to the proper locations.

STP_Port_States.jpg

 

Answer:

- Learning: populating the MAC address table but not forwarding data frames
- Forwarding: sending and receiving data frames
- Listening: preparing to forward data frames without populating the MAC address table
- Blocking: preventing the use of looped paths

Comments
bossy 02-04-2010
on Quest. 5 under access port I thought connect end user workstation before uses a straight through cable to connect device
bossy 02-04-2010
pls correct me
saintdalion 02-05-2010
If any one has problem outside the 9tut or question or may need advice on how i passed and how he too will then he or she should send me an email at saintdalion@yahoo.com and everyone should take 9tut serious.send me an email and lets d
saintdalion 02-05-2010
If any one has problem outside the 9tut or question or may need advice on how i passed and how he too will then he or she should send me an email at saintdalion@yahoo.com and everyone should take 9tut serious.send me an email and lets discuss wat ever u fail proir to ur exam
nayef 02-07-2010
hi guys this Question really confused me alot
can any one help me with it and thanx in advanced

the Question is :
how many subnets can be gained subnetting 172.17.32.0/23 into a /27 mask . and how many usable host addresses will there be per subnet ?


plz guys ASAP!!!
Mr. T 02-07-2010
One subnet taken from 172.17.32.0/23


172.17.32.0/27

30 host per subnet
8 subnets gained with following IPs:
172.17.32.0
172.17.32.32
172.17.32.64
172.17.32.96
172.17.32.128
172.17.32.160
172.17.32.192
172.17.32.224
Rinat 02-08-2010
Mr. T 02-07-2010 thats not truth
/23 is 255.255.254.0 that is subnet 172.17.32.0 and next 172.17.34.0!! total subnets 16!
172.17.32.0
172.17.32.32
172.17.32.64
172.17.32.96
172.17.32.128
172.17.32.160
172.17.32.192
172.17.32.224
172.17.33.0
172.17.33.32
172.17.33.64
172.17.33.96
172.17.33.128
172.17.33.160
172.17.33.192
172.17.33.224
nayef 02-09-2010
to rinat

the only thing that is confusing me is that we are dealing with a class B
ip address so when it is /27 i know or i learned that we should start from
Bit number 17 through 27 which eventually gives us 11 Bit for networks(1s)
so 2^11=2048 subnets

so can u explain the reason it has become only 16 subnets

and thanx in advanced
rinat 02-11-2010
we have subnet mask /23! B class don't play key role, so 27-23 is 4 and 2^4=16.
Shahbaz Ahmed Malhi 02-19-2010
What about Q3? It seems wrong as the order shown in answer. Because to check URL is the ist step in troubleshooting 2nd is checking IP, 3rd NIC and 4th ethernet cable.
9tut 02-19-2010
I added explanation to that question, please check again.
samer 03-01-2010
no its as 9tut told u i had it in my exa :)
kxa 03-14-2010
Hi,

subnetting question:

Both MrT and Rinats' explanations are bad!

first of all, the subnet mask of the private addresses are not the same as public. here are the default prefixes:

10.0.0.0 - 10.255.255.255 /8
172.16.0.0 - 172.31.255.255 /12
192.168.0.0 - 192.168.255.255 /16
like: 192.168.1.0/24 yes it is a SUBnetwork... the default is /16

Now let's see:
172.17.32.0/23 we have 2048 subnet 23-12=11 -> 2^11 = 2048
the subnet mask gained to /27
172.17.32.0/27 we have 2048*16=32768, cos: 27-23=4 -> 2^4 =16
another calculation: 27-12=15 -> 2^15= 32768

But in the real world network we don't use this subnetting, it is just math.
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Last Updated ( Saturday, 20 February 2010 00:41 )