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CCNA – Drag and Drop 5

February 23rd, 2011 Go to comments

Here you will find answers to Drag and Drop Questions – Part 5

Question 1

Drag the Cisco default administrative distance to the appropriate routing protocol or route (Not all options are used)

Default_Administrative_Distance.jpg

 

Answer:

+ RIP: 120
+ OSPF: 110
+ static route referencing IP address of next hop: 1
+ internal EIGRP route: 90
+ directly connected network: 0

Question 2

Drag the term on the left to its definition on the right (not all options are used)

some_rules.jpg

 

Answer:

+ poison reverse: A router learns from its neighbor that a route is down and the router sends an update back to the neighbor with an infinite metric to that route
+ LSA: The packets flooded when a topology change occurs, causing network routers to update their topological databases and recalculate routes
+ split horizon: This prevents sending information about a routeback out the same interface that originally learned about the route
+ holddown timer: For a given period, this causes the router to ignore any updates with poorer metrics to a lost network

Question 3

Drag the description on the left to the correct router mode on the right

Cisco_router_modes copy.jpg

 

Answer:

+ user EXEC mode: limited to basic monitoring commands
+ privileged EXEC mode: provide access to all other router commands
+ global configuration mode: commands that affect the entire system
+ specific configuration mode: commands that affect interfaces/processes only
+ setup mode: interactive configuration dialog

Question 4

Drag each definition on the left to the matching term on the right

Cisco_metric_parameters.jpg

 

Answer:

+ cost: a configurable value based by default on the bandwidth of the interface
+ load: the amount of activity on a network resource
+ bandwidth: the data capacity of a link
+ hop count: the number of point-to-point links in a transmission path
+ reliability: usually refers to the bit error rate of each network link
+ delay: the amount of time required to move a packet from source to destination

Question 5

Refer to the exhibit. Complete the network diagram by dragging the correct device name or description to the correct location. Not all the names or descriptions will be used.

digital_line_CSU_DSU.jpg

 

Answer:

From left to right:

Router, DTE, DCE, CSU/DSU Synchronous, Digital Line, WAN Service Provider Network.

 

Question 6

Drag each feature on the left to the appropriate routing protocol on the right.

RIPv1_OSPF.jpg

 

Answer:

RIP version 1

+ sends frequent updates
+ less complex configuration
+ susceptible to routing loops
+ exchanges full routing table in updates

OSPF:

+ faster convergence
+ uses only event-triggered updates
+ same topology information held by all routers
+ requires more memory and processing power

Question 7

Drag item on left to match item on right

network_type_advantage.jpg

 

Answer:

+ Point to Point Advantage: Quality
+ Point to Point Disadvantage: Limited Flexibility
+ Circuit Switched Advantage: Cost
+ Circuit Switched Disadvantage: Low speed
+ Packet Switch Advantage: Efficient
+ Packet Switch Disadvantage: More Complex

Question 8

All hosts in the same subnet with 172.16.5.118/26 must be denied Telnet access to hosts outside the LAN (u need to just drag & drop) fiil out the command. To complete the bracketed command, [access-list list-number deny tcp 172.16.5.address 0.0.0.mask any eq port], drag each appropriate option on the left to its proper placeholder on the right. (Not all options are used)

access-list-number.jpg

 

Answer:

+ list-number: 128
+ address: 64
+ mask: 63
+ port: 23

Comments (111) Comments
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  1. Arlyss Ballestero
    April 25th, 2013

    hi guys , i make my certification the next month , any recomendation for study?

  2. Salim
    May 14th, 2013

    Study everything in 9tut and the simulations

  3. David Okeri
    May 29th, 2013

    Pliz i will sit for the exam next month, can someone send me the latest dumps on email: olesimbe@yahoo.com

  4. Anonymous
    June 4th, 2013

    Q8 :the address is 64 ,why ???>>thx in advance

  5. soll
    June 9th, 2013

    because the original address is 172.16.5.118/ 26, that means the increment was 64.
    1. 172.16.5.0 – 63
    2. 172.16.5. 64 – 127
    …..
    the 118 address is on the second one. the network address of the second network is 172.16.5.64

  6. loai
    June 9th, 2013

    can anyone explain how the 8th Q solved?

  7. Lu
    June 9th, 2013

    i don t undestend q5….you can HELP me?….tank a lot..

  8. Dave
    June 12th, 2013

    Q8 – Because you are using an extended ACL (defined by port number etc in the command) the acl number has to be between 100-199 or 2000 – 2699. So therefore 128 fits. It states that all hosts in the SUBNET must be denied telnet access so therefore you must subnet 172.16.5.118/26. 64 is increment therefore it is inside the 172.16.5.64/26 subnet – 64 is the address. A /26 has a mask of 255.255.255.192 the wildcard for the ACL is 0.0.0.63 – 63 is the mask. Port well thats easy – 23 is the port number for telnet.

    Q5 – Obviously the Router has the “Router” name. A Router is a Data Terminal Equipment type so DTE fits next to it. The box in the middle represents a CSU/DSU which sends timing to the router therefore it is a Data Communications Equipment or DCE – so DCE fits next to the DTE label. CSU/DSU is just that so it goes underneath the box. The line in theory would most likely be a T1/T3 line and thus would be digital. The cloud represents the WAN Service Provider providing that link to you (for a cost)

  9. Lu
    June 12th, 2013

    usually how many drag and drop in exam?

  10. Dave
    June 13th, 2013

    In my ICND1 I think there was about 3 – 4

  11. Renabamn
    June 17th, 2013

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