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Subnetting Questions

February 6th, 2017 Go to comments

Question 1

Explanation

Network A needs 120 hosts < 128 = 27 -> Need a subnet mask of 7 bit 0s -> “/25″.

Because the ip subnet-zero command is used, network 172.16.3.0/30 can be used.

Answer E “Link A – 172.16.3.40/30″ is not correct because this subnet belongs to MARKETING subnet (172.16.3.32/27).
Answer F “Link A – 172.16.3.112/30″ is not correct because this subnet belongs to ADMIN subnet (172.16.3.96/27).

Question 2

Explanation

Although all above answers are correct but 172.16.1.0/26 is the best choice as it is the most specific prefix-match one.

Question 3

Question 4

Explanation

We need to summarize 4 subnets so we have to move left 2 bits (22 = 4). In this question we can guess the initial subnet mask is /24 because 10.0.0.0, 10.0.1.0, 10.0.2.0, 10.0.3.0 belong to different networks. So “/24″ moves left 2 bits -> /22.

Question 5

How many usable host are there per subnet if you have the address of 192.168.10.0 with a subnet mask of 255.255.255.240?

A. 4
B. 8
C. 16
D. 14

 

Answer: D

Explanation

From the subnet mask of 255.255.255.240 (/28) we learn there are 24 – 2 = 14 hosts per subnet.

Comments (11) Comments
  1. jasin
    March 6th, 2017

    You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while providing the maximum number of subnets. Which network address and subnet mask meet this requirement?
    A. 192.168.252.0 255.255.255.252
    B. 192.168.252.8 255.255.255.248
    C. 192.168.252.8 255.255.255.252
    D. 192.168.252.16 255.255.255.240
    E. 192.168.252.16 255.255.255.252
    any one please could explain how we goina work out for 3 web server

  2. skyflakes
    March 7th, 2017

    We want to have 3 host right or 3 web servers? so B is correct because of the subnet. 255.255.255.248 or /29. the increment of it is 8. 8 – 2 = 6 usable host, so it would fit the requirements,

  3. Aaron
    March 7th, 2017

    8 – 2 because we subtract the network id and broadcast id. So we could only use 6 host, unlike in letter C for instance is 255.255.255.252. so it’s 30. the increment is 4 so 4 – 2 = 2 host only, so it wouldn’t match the needed requirements for 3. i hope my answer is correct. :)

  4. Eriol
    March 9th, 2017

    Both Skyflakes and Aaron are correct (: because you need to use a mask of /29 to have 6 usable IP’s to configure your “3” needed host, the masks /30 only gives you 2 usable IPs which doesn’t meet the requirements of 3 hosts and the /28 mask gives you 14 usable IPs, which doesn’t fullfil the “while providing the maximum number of subnets” statement.

  5. Hicham
    April 4th, 2017

    Sorry i don’t see quetions???

  6. Henchman
    April 7th, 2017

    Just at first glance of your answers I would say either ” B ” or ” C ” could be used, but then I had to look at your Subnet Mask in the last octet, and knowing that I need to provide for 3 Web Servers and give them IP Addresses from my subnet mask, I would have to borrow 5 bits from left to right giving me a mask ending with 248, i.e 255.255.255.248, and the 5 borrowed bits will give me 8 host minus the broadcast and IP so I will have 6 usable IP addresses for the 3 Web Servers leaving me with 2 left over IP for other devices……that is how I would do it !!!!!

  7. Vince
    April 30th, 2017

    Why do you say subnet hosts. This kind of vocabulary is common among people who don’t know how the technology is used correctly.

  8. Ricky
    May 13th, 2017

    Need help#
    Suppose You have a big company of 63 hosts per network. You are the System Administrator of your company. You have to plan the addressing scheme. Your are given IP 172.72.157.253 And your Dept. (Engtneering) uses Subnet N 399.
    Q. What will be the Subnet bit?

  9. MUhammad Mohyuddin
    May 16th, 2017

    You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while providing the maximum number of subnets. Which network address and subnet mask meet this requirement?

    B. 192.168.252.8 255.255.255.248

  10. davegi
    May 22nd, 2017

    why the payment method is only paypal? any other options like mastercard and others