CCNA – EIGRP Questions
Here you will find answers to EIGRP Questions
Note: If you are not sure about EIGRP, please read my EIGRP tutorial
Question 1
Refer to the exhibit, when running EIGRP what is required for R1 to exchange routing updates with R3?

A – AS numbers must be changed to match on all the routers
B – Loopback interfaces must be configured so a DR is elected
C – The no auto-summary command is needed on R1 and R3
D – R2 needs to have two network statements, one for each connected network
Answer: A
Question 2:
As a Cisco technician, you need to know EIGRP protocol very well. Which of the following is true about EIGRP successor routes? (Choose two)
A – A successor route is used by EIGRP to forward traffic to a destination
B – Successor routes are stored in the neighbor table following the discovery process
C – Successor routes are flagged as “active” in the routing table
D – A successor route may be backed up by a feasible successor route
Answer: A D
Explanation:
B is not correct because neighbor table only contains a list of directly connected EIGRP routers that have an adjacency with this router, it doesn’t contain successor routes.
C is not correct because successor routes are not flagged as “active”, they are always the best route to reach remote networks and are always used to send packets.
A and D are correct because successor route is the best and primary route to a remote network. It is stored in the routing table and topology table. If this route fails, a backup route (called feasible successor route) in the topology table will be used to route traffic to a destination.
Question 3:
Which two statements are true regarding EIGRP? (Choose two)
A – Passive routes are in the process of being calculated by DUAL
B – EIGRP supports VLSM, route summarization, and routing update authentication
C – EIGRP exchanges full routing table information with neighboring routers with every update
D – If the feasible successor has a higher advertised distance than the successor route, it becomes the primary route
E – A query process is used to discover a replacement for a failed route if a feasible successor is not identified from the current routing information
Answer: B E
Explanation:
Diffusing Update Algorithm (DUAL) is the algorithm for selecting and maintaining the best path to each remote network. DUAL tracks all the routes advertised by neighbors and selects routes based on feasible successors. It inserts lowest cost paths into the routing table (these routes are known as primary routes or successor routes) -> A is not correct.
EIGRP is still a distance-vector protocol, but has certain features that belong to link-state algorithms (like OSPF) than distance-vector algorithms. For example, EIGRP sends a partial routing table update, which includes just routes that have been changed, not the full routing table like distance-vector algorithms -> C is not correct.
The feasible successor route will become the primary route when its advertised distance is lower than the feasible distance of the successor route. The feasible successor route can be used in the event that the successor route goes down. Notice that the feasible successor route does not get installed in the routing table but is kept in the topology table as a backup route -> D is not correct.
“Support VLSM, route summarization, and routing update authentication” are the features of EIGRP -> B is correct.
When a route fails and has no feasible successor, EIGRP uses a distributed algorithm called Diffusing Update Algorithm (DUAL) to discover a replacement for a failed route. When a new route is found, DUAL adds it to the routing table -> E is correct.
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@9tut:
I request you to Please review and explain Q3. I read couple of comments about having it wrong. I also think there is something missing in the explaination.
Thanks!
@Nash D: Yes, the explanation is not correct with the word “higher”, I updated it
“The feasible successor route will become the primary route when its advertised distance is higher than the feasible distance of the successor route”.
Thanks for your detection!
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Can someone help with understanding this problem. The question was taken from one of the dumps: Please help, I thought it would be dropped.
Question:
Refer to the exhibit. A packet with a source IP address of 192.168.2.4 and a destination IP address of 10.1.1.4 arrives at the HokesB router. What action does the router take?
exhibit:
HokesB# show ip route
192.168.2.0/28 is subnetted, 6 subnets
D 192.168.2.64 [90/20514560] via 1923168.0.6, 01:22:10, Serial0/1
D 192.168.2.80 [90/20514560] via 192.168.0.6, 01:22:10, Serial0/1
D 192.168.2.32 [90/20514560] via 192.168.9.2, 01:22:10, Serial0/0
D 192.168.2.48 [90/20514560] via 192.168.9.2, 01:22:10, Serial0/0
D 192.168.2.0 [90/30720] via 192.168.1.10, 01:22:10, FastEthernet0/0
D 192.168.2.6 [90/156160] via 192.168.1.10, 01:22:10, FastEthernet0/0
192.168.9.0 is subnetted, 1 subnets
C 192.168.9.0/30 is directly connect, to Serial0/0
192.168.0.0/30 is subnetted, 1 subnets
C 192.168.0.4 is directly connect, to Serial0/1
192.168.1.0 is subnetted, 1 subnets
C 192.168.1.8 is directly connect, to FastEthernet0/0
HokesB#
A. forwards the received packet out the Serial0/0 interface
B. forwards a packet containing an EIGRP advertisement out the Serial0/1 interface
C. forwards a packet containing an ICMP message out the FastEthernet0/0 interface
D. forwards a packet containing an ARP request out the FastEthernet0/1 interface
Answer: C
@bubbatx
“…and a destination IP address of 10.1.1.4…”
i don’t see any entries for 10.0.0.0 or for a subnet that would include 10.1.1.4 in the output provided.
i don’t see anything regarding the gateway of last resort.
this packet WILL BE DROPPED.
now… what happens next is what interests us.
HokesB has to inform the source of this packet that the destination was unreachable. this is done by using an ICMP message.
only option C matches our criterion of “ICMP message”.
also… the packet came from 192.168.2.4 which is part of…
D 192.168.2.0 [90/30720] via 192.168.1.10, 01:22:10, FastEthernet0/0
we also know that this subnetwork has a subnet mask of /28 (from the output: 192.168.2.0/28 is subnetted, 6 subnet)
the packet came from 192.168.2.0/28 which is reachable on Fa0/0.
to conclude:
the packet is dropped
an ICMP message is sent
the ICMP message leaves via Fa0/0
Correct answer: C
@xallax
Thanks a million. I got it. I hadn’t consider the network unreachable message.
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@anonymous
try http://www.ciscovce.com
Can someone please forward the latest CCNA or ICND2 dump to datc1912@yahoo.com. I am taking the test on Monday and would greatly appreciate any assistance. Thank You.
hi one important question
if we have 3 subnetwork : 10.43.80.32/27 , 10.43.80.64/27 , 10.43.80.128/27 how will configure eigrp
1===> network 10.43.80.32
network 10.43.80.64
network 10.43.80.128
no auto summary
or
2====> network 10.0.0.0
no auto summary
plz urgent and thanks in advance
@jawad
2nd option
we can also give like this
network 10.43.80.0
no auto summary
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Taking exam next friday
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atulraikar@gmail.com
@CCNA guys plz reply this Q in this picture
http://img102.herosh.com/2011/12/03/534395738.jpg
my answer would be from R3 to R1 as EIGRP uses bandwidth, delay, cost, MTU, reliability.
so why is the answer is D as cost will be higher !!???
thanks in advance
@eng-support
take a look at the exhibit, it shows you 2 eigrp routes, both have equal metric values.
Answer D is correct: R3 would load-balance by sending half the packets to R1 and half to R2
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@xallax thanks it was out of my head :) :)
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@9tut
I’m still confused with this explanation:
“The feasible successor route will become the primary route when its advertised distance is lower than the feasible distance of the successor route. The feasible successor route can be used in the event that the successor route goes down. Notice that the feasible successor route does not get installed in the routing table but is kept in the topology table as a backup route -> D is not correct.”
Perhaps you mean that a route can become a feasible successor if it’s AD is lower than the feasible distance of the successor route? and then it will become a primary route once the successor route goes down.
@tohritz: Yes, it is what I mean!
@9tut:
Thanks for the clarification mate. I’m taking the exam by the 3rd week of January. Your site really helps a lot.
hey guys – i found a free eigrp configuration video:
http://www.bosscbt.tv/icnd2/eigrp-required-configurations-verification/
enjoy!
Can someone please provide me the latest dumps, email – patel_divyesh13@hotmail.com.
Thanks in advance.
i want to inquire about the 1st question that AS number should b same in order to communicate but in question 1 the answer is to change the AS number. how?
@tariq: For example, EIGRP AS number should be 300:
R1>en
R1#conf t
R1(config)#router eigrp 300
R1(config-router)#network 172.16.0.0
R1(config-router)#network 10.0.0.0
R1(config-router)#exit
R1(config)#exit
R1#copy run start
R2>en
R2#conf t
R2(config)#router eigrp 300
R2(config-router)#network 10.0.0.0
R2(config-router)#exit
R2(config)#exit
R2#copy run start
After that EIGRP AS number will be the same and routers will able to communicate.
thnx alot DimS
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Hi everyone,
Would you guys please explain for me this question:
http://img103.herosh.com/2012/01/03/792457050.jpg
Thanks in advance.
In that question, I dont know what they based on to get the answer F. As we know, there are maximum 4 equal-cost paths by default in routing table.
The variance number for calculate equal-cost paths is used as following rule:
Variance number x FD = product
Any FS who metric is less than above product is considered to be equal route and may be placed in routing table.
In the output exhibit, we have 2 noticeable numbers:
-the variance number is set 3
-maximum equal-cost paths is 4.
Hm, still dont get it. ???
Question guys regarding eigrp configuration. i guess there are a lot of ways on how to advertise the network. What’s the best way and why would you think this is better than the others?
example for networks: 192.168.1.0 /24; 172.168.16.0/24; and 10.11.8.0/24
Would it be a better option to include a wild card like:
router eigrp 100
network 192.168.1.0 0.0.0.255
network 172.168.16.0 0.0.0.255
network 10.11.8.0 0.0.0.255
no auto-summary
a bit confused, since i read somewhere that i can also use a summary wild card.
TIA
@hai
i think “variance X” means that the router will use paths that have a cost of as low as 1/X of the best path… am i wrong?
@xallax:
Let see what is the definition of the variance.
According to Wendell Odom, page 400 of the CCNA ICND 2 book:
“variance allows routes who metrics are relatively close in value to be considered equal, allowing multiple unequal-metric routes to the same subnet to be added to the routing table”
“Variance multiplier EIGRP router subcommand defines an interger between 1 and 128. The router then multiplies the variance times a route’s FD- the best metric with which to reach that subnet. Any FS routes who metric is less than the product of variance times the FD are considered to be equal routes and may be placed in the routing table, depending on the setting of the maximum-paths command”
Example from that book: routes from R4 to a certain network through R1, R2, and R3 have metrics (50/30), (90/40), and (120/60) respectively—> the successor route is 50 (FD)-the route through R1; and the FS is 40- the route through R2.
-If variance is 1 then we have 50×1=50–> route through R1 is added to routing table because it matches exactly with the successor route (definitely equal).
-If variance is 2 then we have 50×2=100—> routes through R1 and R2 were added to routing table because their FD 50 and 90 respectively lower than 100.
-If variance is 3 then we have 50×3= 150—> all three FDs are less than 150 but the route through R3 is NOT added to routing table because its FD is not the FS.
That’s all about the variance number.
Hm, this question is fairly tricky.
All the answers mention to equal or unequal-cost path that makes me think of the variance, but the question is about the processing of forward packets to a neighbor router, NOT for a network, that makes me think of the two gateways with the default distance (90).
Anyone help me out???
All right, I might explain that answer as following:
-if the variance is not 1 (default) that means the router will load UNEQUAL-cost paths to its routing table.
-the maximum paths cost by the default is 4 (can be set up to 16)
Hi eveyone,
I just ask my master about that question, he said because the output exhibits that there are two gateways for 2 neighbors, therefore the answer should be 2 unequal-cost paths. Any comment?
@hai
so… a maximum of 4 paths if there were 4 gateways?
@xallax:
Yes, the number of gateways will tell us about actual paths to get the neighbors
@hai
so the answer is 2 unequal cost paths… brilliant :)
thank you for sharing this
Question guys regarding eigrp configuration. i guess there are a lot of ways on how to advertise the network. What’s the best way and why would you think this is better than the others?
example for networks: 192.168.1.0 /24; 172.168.16.0/24; and 10.11.8.0/24
Would it be a better option to include a wild card like:
router eigrp 100
network 192.168.1.0 0.0.0.255
network 172.168.16.0 0.0.0.255
network 10.11.8.0 0.0.0.255
no auto-summary
a bit confused, since i read somewhere that i can also use a summary wild card.
TIA
For variance, just say you have 4 paths. and by default variance is one meaning it will not unequal-cost load balance…it will take the path with best OVERALL bandwidth/delay metric of the 4, meaning the addition of all bandwidths of all routers and connections from start to finish. Hence, eigrp shares topology tables of all routers in its autonomous system AS, and puts its best path in the routing table. but there should be many feasible paths in the topology table , too for this to work.
so path
1. 550 + 725 = 1275
2. 1250 + 1310= 2560
3. 2200 + 635 = 2835
4. 1500 + 100 + 635 = 2235
by default, path 1 wins because it has the lowest value. but now you want to unequal load 2 paths. so you would pick the second best. You must multiply the best by 2 and see if that value is less than the second best. if it is then you would use command variance 2. Hence, 2 times 1275 is 2550, and 2550 is more than 2235, the second best. if it was higher than 2550 than maybe a variance 3 command, just do the simple math.
with EIGRP you have the option to use wild card mask but not mandatory, if you do it just makes the summarization process a little different in a better way, maybe more accurate or just simply the way you want it.
If you take the no auto summary approach with no mask, then it will see the tables as classful since eigrp is hybrid. adding masks will make the CIDR process perform. i recommend no auto summary with the masks.
@eddie:
if i use the no auto-summary approach with no mask, how will i type the network statement?
network 10.0.0.0
no auto-summary
or
network 10.11.8.0
no auto-summary
with no auto summary and no mask, it sees it like RIPv1 does
both are Class a and so they have no mask, so they will be tied together in the routing process like RIPv1.
it is hard to believe, but EIGRP will work like RIPv1 if no mask is used….reguardless if there is no auto sum or not… In the exam, you dont have to worry about it…because they give you class c.
with no submasks, static routes are used down the paths of the remote routers…
@eddie
you mentioned about RIPv1, what about RIPv2? say my loopback address is: 10.0.8.1 /24, what shall i type to advertise the network?
router rip
version 2
network 10.0.0.0
no auto-summary
or
router rip
version 2
network 10.0.8.0
no auto-summary
Can Someone please send me the latest dump, i am going to take the exam next week.
hd1expectra@pelayo.com
Hi Guys.
Have a question. I read somewhere on these comments that the EIGRP supports upto a maximum of 16 unequal -cost paths. I also read from the CCNA Portable Command Guide that the maximum number of paths supported are 6. Someone please clarify this as am confused.
Thanks
there is no any difference you can any one . but thing that wild card mask is optional .if you are confuse do one thing take 2 router and in 1 router use normal and in the 2ed router use wild card .i already done this there no any difference.one’s again wildcard mast is OPTIONAL.
Have a question. I read somewhere on these comments that the EIGRP supports upto a maximum of 16 unequal -cost paths. I also read from the CCNA Portable Command Guide that the maximum number of paths supported are 6. Someone please clarify this as am confused.
see thing that by defult eigrp support 4 equal lode balance and eigrp support across up to 16 equal or unequal links…
Thank you everyone for information.
Can anyone please send me the dumbs you are talking about? berthavillamil7@hotmail.com Thank you
Thank you BfromA it was nice video
http://www.bosscbt.tv/icnd2/eigrp-required-configurations-verification
am going to take ma xam on this 2nd feb(third attempt)…if any new dumps inform me pls..thanks in advance
hello all
Can we use ” ? ” operator in exam simulator?
Yes we can use ? in exam simulator
passive-interface …” command somewhere in R1 configuration. in the above sim 9tut explained abt that(in eigrp lab qtn)…then using which command we will check that 1 is present or not….iam going to write ma xam tomorrow so pls give me a fast rply…..thanks in advance
Hi,
I have no idea how to practical question will be like in exam. can anyone tell me the how it will be. if you have any pdf which helps me to prepare for exam pls mail to harish7722@gmail.com
Hi 9tut… Hi Guys! Can you please help me… I will take exam this Feb. Please send me latest dump so that I will have an idea for the exam.. rico.blake@ymail.com
Thanks Guys!
How can i advertise a default route using eigrp?
@Sofia: e.g.:
Int f0/0 – link with default route
conf t
ip route 0.0.0.0 0.0.0.0 192.168.10.2
int f0/0
ip add 192.168.10.1
exit
router eigrp AS_NUMBER
redist static
passive f0/0
net x.x.x.x
net y.y.y.y
^Z
@DimS
Thank you so much. Its working
Passed my CCNA exam 31-02-2012
Got Marks 881/1000
Very important LABS Eigrp.
MUST MUST MUST
Passed my CCNA exam 31-02-2012
Got Marks 881/1000
Very important LABS Eigrp.
MUST MUST MUST
faisalfcc2004@gmail.com